A train runs with the speed of 72 km/h. It reaches its destination late by 15 minutes. However, if speed is 90 km/h, it is late by only 5 minutes. The correct time (min) to cover its journey and find distance. |
35, 60 45, 60 35, 70 45, 70 |
35, 60 |
Speed ⇒ 72 : 90 4 : 5 time ⇒ 5 : 4 ... (diff. 1 → ×10 → 10) ↓ ×10 ↓ 50 min Correct time = 50 - 15 = 35 min D = 72 × \(\frac{50}{60}\) = 60 km |