Practicing Success
Find the least number which when divided by 5, 8, 11, 15 and 18 leaves the same remainder 7 in each case. |
3569 3987 3967 4089 |
3967 |
Required number must be the L.C.M of 5, 8, 11, 15 and 18 with an addition of 7. Now, L.C.M. of 5, 8, 11, 15 and 18 = 3960 So, required number = (3960 + 7) ⇒ 3967 |