A does half as much work as B in 1/6th of the time. If together they take 10 days to complete a work, then how much time shall B take to do it alone ?
Answer & explanation
Correct answer: option 3
Let B takes x days to complete the work
According to question ,
Time taken by A to complete the work = 2 × \(\frac{1x}{6}\) = \(\frac{x}{3}\)
Together they can finish a piece of work in 10 days .
( A + B )'s 1 day work = \(\frac{1}{10}\)
Now , \(\frac{1}{x}\) + \(\frac{3}{x}\) = \(\frac{1}{10}\)
x = 40
Hence B takes 40 days to complete the work