Practicing Success
The area bounded by the curve $y=x^2$ between $x=0$ and $x = \pi $, in the first quadrant is : |
0 $\pi^3/3$ 2 $4\pi^3/3$ |
$\pi^3/3$ |
The correct answer is Option (2) → $\pi^3/3$ area = $\int\limits_0^{\pi}x^2dx$ $=\left[\frac{x^3}{3}\right]_0^{\pi}$ $=\frac{\pi^3}{3}$ |