The area bounded by the curve $y=x^2$ between $x=0$ and $x = \pi $, in the first quadrant is :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\pi^3/3$
area = $\int\limits_0^{\pi}x^2dx$
$=\left[\frac{x^3}{3}\right]_0^{\pi}$
$=\frac{\pi^3}{3}$