Practicing Success
Practicing Success
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If $a = 11$, and $b = 9$, then the value of $\left(\frac{a^2+b^2+ab}{a^3-b^3}\right)$ is: |
2 $\frac{1}{2}$ 20 $\frac{1}{20}$ |
$\frac{1}{2}$ |
We have, $a = 11$, and $b = 9$ So, put them in, $\left(\frac{a^2+b^2+ab}{a^3-b^3}\right)$ $\left(\frac{11^2+9^2+11×9}{11^3-9^3}\right)$ = \(\frac{301}{1331 - 729}\) = \(\frac{301}{602}\) = \(\frac{1}{2}\) |
