Practicing Success
For $I=\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]$, if X and Y are square matrices of order 2 such that $X Y=X$ and $Y X=Y$, then $\left(Y^2+2 Y\right)$ equals to: |
$2 Y$ $I+3 X$ $I+3 Y$ $3Y$ |
$3Y$ |
The correct answer is Option (4) → $3Y$ |