If $A =\begin{bmatrix}5&1\\-2&0\end{bmatrix}$ and $B^T=\begin{bmatrix}1&10\\-2&-1\end{bmatrix}$, then the matrix AB is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\begin{bmatrix}15&-11\\-2&4\end{bmatrix}$
$A =\begin{bmatrix}5&1\\-2&0\end{bmatrix}$
$B^T=\begin{bmatrix}1&10\\-2&-1\end{bmatrix}$
$⇒B=\begin{bmatrix}1&-2\\10&-1\end{bmatrix}$
$AB=\begin{bmatrix}5&1\\-2&0\end{bmatrix}\begin{bmatrix}1&-2\\10&-1\end{bmatrix}$
$=\begin{bmatrix}15&-11\\-2&4\end{bmatrix}$