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The value of $\int\limits_{-\frac{\pi}{2}}^{\frac{\pi}{2}}\left(x^3+x \cos x+\tan ^5 x+1\right) d x$ is: |
0 2 $\pi$ 1 |
$\pi$ |
The correct answer is Option (3) → $\pi$ $\int\limits_{-\frac{\pi}{2}}^{\frac{\pi}{2}}\left(x^3+x \cos x+\tan ^5 x+1\right) d x$ $=\int\limits_{-\frac{\pi}{2}}^{\frac{\pi}{2}}\left(1\right) d x$ $=\pi$ |
