Match the LIST-I with LIST-II.
| LIST-I Cell/Electrode reaction | LIST-II Reaction involved in |
| A. Zn(Hg) + HgO(s) → ZnO(s) + Hg(l) | I. Fuel cell |
| B. 2H2(g) + O2(g) → 2H2O(l) | II. Reference electrode |
| C. Pb(s) + PbO2(s) + 2H2SO4(aq) → 2PbSO4(s) + 2H2O(l) | III. Primary battery |
| D. H+(aq) + e− → ½H2(g) | IV. Secondary battery |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → A-III, B-I, C-IV, D-II
Electrochemical devices are grouped by how their reaction is used:
Primary battery: the reaction occurs only once and cannot be reversed; once the reactants are used up, the cell is dead (dry cell, mercury cell).
Secondary battery: the reaction can be reversed by passing current in the opposite direction, so the battery can be recharged (lead storage battery, nickel–cadmium cell).
Fuel cell: converts the energy of combustion of a fuel such as H2 directly into electricity; the reactants are supplied continuously.
Reference electrode: its potential is fixed and all other electrodes are measured against it; the standard hydrogen electrode is given the value 0 V.
A. Zn(Hg) + HgO(s) → ZnO(s) + Hg(l) — This matches III. Primary battery. This is the cell reaction of the mercury cell, used in watches and hearing aids. It gives a steady 1.35 V and cannot be recharged.
\( \displaystyle \text{Anode: }\ce{Zn(Hg) + 2OH^- -> ZnO(s) + H2O + 2e^-} \)
\( \displaystyle \text{Cathode: }\ce{HgO(s) + H2O + 2e^- -> Hg(l) + 2OH^-} \)
B. 2H2(g) + O2(g) → 2H2O(l) — This matches I. Fuel cell. In the H2–O2 fuel cell, hydrogen and oxygen are bubbled through porous carbon electrodes into concentrated NaOH solution, and the only product is water.
\( \displaystyle \text{Anode: }\ce{2H2(g) + 4OH^-(aq) -> 4H2O(l) + 4e^-} \)
\( \displaystyle \text{Cathode: }\ce{O2(g) + 2H2O(l) + 4e^- -> 4OH^-(aq)} \)
C. Pb(s) + PbO2(s) + 2H2SO4(aq) → 2PbSO4(s) + 2H2O(l) — This matches IV. Secondary battery. This is the discharge reaction of the lead storage battery. On charging, the reaction runs backwards and \( \ce{PbSO4} \) is converted back into Pb and \( \ce{PbO2} \). On discharge:
\( \displaystyle \text{Anode: }\ce{Pb(s) + SO4^2-(aq) -> PbSO4(s) + 2e^-} \)
\( \displaystyle \text{Cathode: }\ce{PbO2(s) + SO4^2-(aq) + 4H^+(aq) + 2e^- -> PbSO4(s) + 2H2O(l)} \)
D. H+(aq) + e− → ½H2(g) — This matches II. Reference electrode. This is the half reaction of the standard hydrogen electrode, whose E° is taken as 0 V at all temperatures.
Shortcut: The pair C–IV appears only in Option (2).