A \(11\,\mu\mathrm{F}\) capacitor is charged by \(220\,\mathrm{V}\) battery. The electrostatic energy stored in the capacitor is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \(0.266\,\mathrm{J}\)
The energy stored in a charged capacitor is the work done in charging it.
\( \displaystyle U = \frac{1}{2}CV^{2} \)
\( \displaystyle U = \frac{1}{2} \times (11\times10^{-6}\,\mathrm{F}) \times (220\,\mathrm{V})^{2} \)
\( \displaystyle U = \frac{1}{2} \times 11\times10^{-6} \times 48400\,\mathrm{J} \)
\( \displaystyle U \approx 0.266\,\mathrm{J} \)
Note: NTA picked this question from an NCERT (2026-27) exercise and changed the figures. Do not ignore NCERT while practising numericals.
NCERT (2026-27):
Exercises – …
