Match the LIST-I with LIST-II (Symbols have their usual meaning)LIST-…

The correct answer is Option (4) → A-IV, B-III, C-I, D-II

In a magnetic material the field B has two parts: one due to the magnetic intensity H and one due to the magnetisation M of the material. The other quantities follow from this relation.

(A) Magnetic susceptibility — this matches (IV) M H⁻¹. Susceptibility measures how strongly a material is magnetised by a given intensity.

    \( \displaystyle \chi = \frac{M}{H} \)

(B) Magnetic permeability — this matches (III) μ₀(1 + χ). Substituting \( M = \chi H \) in \( B = \mu_0(H + M) \) gives \( B = \mu_0(1 + \chi)H = \mu H \).

    \( \displaystyle \mu = \mu_0(1 + \chi) \)

(C) Magnetic field — this matches (I) μ₀(H + M). The total field inside the material is the sum of the contributions of the intensity and the magnetisation.

    \( \displaystyle B = \mu_0(H + M) \)

(D) Relative magnetic permeability — this matches (II) B (μ₀ H)⁻¹. It is the ratio of the permeability of the material to that of free space, \( \mu_r = \mu/\mu_0 \), and \( \mu = B/H \).

    \( \displaystyle \mu_r = \frac{B}{\mu_0 H} \)

NCERT (2026-27):
Summary – “… The magnetisation \( \mathbf{M} \) of the material is its dipole moment per unit volume. The magnetic field \( \mathbf{B} \) in the material is,
    \( \mathbf{B} = \mu_0(\mathbf{H} + \mathbf{M}) \)
6. For a linear material \( \mathbf{M} = \chi\mathbf{H} \). So that \( \mathbf{B} = \mu\mathbf{H} \) and \( \chi \) is called the magnetic susceptibility of the material. The three quantities, \( \chi \), the relative magnetic permeability \( \mu_r \), and the magnetic permeability \( \mu \) are related as follows:
    \( \mu = \mu_0\,\mu_r \)
    \( \mu_r = 1 + \chi \)”