Corner points of the bounded feasible region for an LPP are \( (0,2) \), \( (3,0) \), \( (6,0) \), \( (0,5) \) and \( (6,8) \). Let \( z=4x+6y \) be the objective function. Then \( \max z-3(\min z)= \)
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 36
The value of \( z=4x+6y \) at each corner point is:
\( \displaystyle (0,2):\ z=12 \)
\( \displaystyle (3,0):\ z=12 \)
\( \displaystyle (6,0):\ z=24 \)
\( \displaystyle (0,5):\ z=30 \)
\( \displaystyle (6,8):\ z=72 \)
So max z = 72 and min z = 12.
\( \displaystyle \max z-3(\min z)=72-3(12) \)
\( \displaystyle =36 \)