The angular momentum of the electron in n=2 orbit in hydrogen atom is

The correct answer is Option (3) → \( 2.1\times10^{-34}\,\mathrm{kg\,m^{2}s^{-1}} \)

By Bohr’s quantisation condition, the angular momentum of the electron in the n-th orbit is an integral multiple of \( h/2\pi \):

    \( \displaystyle L = \frac{nh}{2\pi} \)

    \( \displaystyle L = \frac{2\times6.63\times10^{-34}}{2\times3.14} = \frac{6.63\times10^{-34}}{3.14} \)

    \( L \approx 2.1\times10^{-34}\,\mathrm{kg\,m^{2}s^{-1}} \)