A parallel plate capacitor has capacitance \( 120\ \mathrm{F} \) when there is no dielectric medium between the plates. If the space between the plates of the capacitor is filled with a dielectric slab of dielectric constant \( 5 \), then, the new capacitance of the capacitor will be
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \( 600\ \mathrm{F} \)
When a dielectric fills the whole space between the plates, the field between the plates is reduced \( K \) times for the same charge, so the potential difference falls and the capacitance increases \( K \) times.
\( C = KC_{0} = 5 \times 120\ \mathrm{F} = 600\ \mathrm{F} \)