In an electrical circuit, two resistors, \( R_{1} \) and \( R_{2} \), are connected in parallel across a battery of emf \( E \). The ratio \( (I_{1} : I_{2}) \) of the currents \( I_{1} \) and \( I_{2} \) flowing through resistors, \( R_{1} \) and \( R_{2} \), respectively, is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \( R_{2} : R_{1} \)
Resistors in parallel have the same potential difference E across them, so by Ohm’s law the current in each is inversely proportional to its resistance.
\( I_{1} = E/R_{1} \)
\( I_{2} = E/R_{2} \)
\( \displaystyle \frac{I_{1}}{I_{2}} = \frac{E/R_{1}}{E/R_{2}} = \frac{R_{2}}{R_{1}} \)