In the Faraday experiment, North-pole of a bar magnet is being pushed towards the closed coil. The induced current in the coil
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → is produced in an anticlockwise direction with respect to an observer situated on the side of the magnet.
By Lenz’s law the induced current opposes the change that produces it. As the N pole approaches, the flux through the coil increases, so the induced current makes the face of the coil nearer the magnet a north pole, which repels the approaching magnet.
A face behaves as a north pole when the current in it, seen from that side, flows anticlockwise. So an observer on the magnet’s side sees an anticlockwise current.
Why the other options are incorrect
Option (1) is produced in a clockwise direction with respect to an observer situated on the side of the magnet. — Incorrect. A clockwise current (a south pole facing the magnet) is induced when the N pole is withdrawn, or when an S pole is pushed in.
Option (3) will be alternating current — Incorrect. The current flows one way while the magnet approaches.
Option (4) will not be produced — Incorrect. The flux through the closed coil changes, so a current is induced.
NCERT (2026-27):
Lenz’s Law and Conservation of Energy – “… In Fig. 6.1, we see that the North-pole of a bar magnet is being pushed towards the closed coil. As the North-pole of the bar magnet moves towards the coil, the magnetic flux through the coil increases. Hence current is induced in the coil in such a direction that it opposes the increase in flux. This is possible only if the current in the coil is in a counter-clockwise direction with respect to an observer situated on the side of the magnet.”