Practicing Success
A fair die is rolled. Consider events E = {1, 3, 5} , F = {2, 3} and G= {2, 3, 4, 5} then find P((E∪F)IG)-
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1/4 3/4 2/3 1/3 |
3/4 |
When a fair die is rolled, the sample space S will be S = {1, 2, 3, 4, 5, 6} It is given that E = {1, 3, 5} , F = {2, 3} and G= {2, 3, 4, 5} So, P(E) = 3/6 = 1/2 P(F) = 2/6 = 1/3 P(G) = 4/6 = 2/3 We know that P((E∪F)IG) = P((E∪F)∩G)/ P(G) E∪F = {1, 2 , 3 , 4} (E∪F)∩G = {1, 2 , 3 , 4}∩{2, 3, 4, 5} = {2, 3, 5} P{(E∪F)∩G} = 3/6= 1/2 Hence P((E∪F)IG) = (1/2)/(2/3) = 3/4 |