An airplane goes 14 km due east and then 48 km due north. How far is it from its initial position?

14 km 48 km 50 km 28 km

50 km

⇒ Using pythagoras theorem, ⇒ \( {14 }^{2 } \) + \( {48 }^{2 } \) = 196 + 2304 = 2500 ⇒ \(\sqrt { 2500}\) = 50 Km. Therefore, plane is 50 Km far from the initial point.