The corner points of the feasible region for an L.P.P are (0, 7), (8, 8), (9, 3) and (0, 15). If the objective function is $Z=px +qy : p, q > 0,$ then the condition on p and q so that the maximum of Z occurs at (0, 7) and (9, 3) is : |
$3p=2q$ $2p=q$ $9p=4q$ $7p=2q$ |
$9p=4q$ |
The correct answer is Option (3) → $9p=4q$ The objective function, $Z=px +qy$ $Z(0,7)=Z(9,3)$ [Given] $7q=9p+3q$ $4q=9p$ |