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a b c d |
b |
The correct answer is Option (2) → b $A=\begin{bmatrix}3\\1\\2\end{bmatrix}$ $B=\begin{bmatrix}2&0&5\end{bmatrix}$ $AB=\begin{bmatrix}3\\1\\2\end{bmatrix}\begin{bmatrix}2&0&5\end{bmatrix}=\begin{bmatrix}6&0&15\\2&0&5\\4&0&10\end{bmatrix}$ |
