Practicing Success
HCF of two numbers is 18. If the sum of these two numbers and their LCM is 990. How many pairs of such numbers are possible? |
2 3 1 5 |
1 |
Let a, b are two coprime numbers, then 18a + 18b + 18ab = 990 a + b + ab = \(\frac{990}{18}\) = 55 add 1 both sides. (1 + a) (1 + b) = 56 = 1 × 56 ..... (not possible) = 2 × 28 ..... (i) = 4 × 14 ..... (ii) = 7 × 8 ..... (iii) (i) and (ii), they all have common factor 2. So, pairs (only 1) |