If $k - \frac{3}{k} = 5,$ then what is the value of $k^2 + \frac{9}{k^2}$ ?

31 25 11 19

31

If $k - \frac{3}{k} = 5,$ then what is the value of $k^2 + \frac{9}{k^2}$= ? We know that, If x - \(\frac{1}{x}\)  = n then, x2 + \(\frac{1}{x^2}\)  = n2 + 2 If $k - \frac{3}{k} = 5,$ then, $k^2 + \frac{9}{k^2}$ = 52 + 2 × 3 = 31