If k - 3/k = 5, then what is the value of k^2 + 9/(k^2) ?

If $k - \frac{3}{k} = 5,$

then what is the value of $k^2 + \frac{9}{k^2}$= ?

We know that,

If x - \(\frac{1}{x}\)  = n

then, x² + \(\frac{1}{x^2}\)  = n² + 2

If $k - \frac{3}{k} = 5,$

then, $k^2 + \frac{9}{k^2}$ = 5² + 2 × 3 = 31