A man travels by train at the speed of 25 km/hr and comes back by foot at the speed of 4 km/hr. If he takes total 5 hours 48 min for travel the whole journey, then find distance (in km) . |
15 20 25 28 |
20 |
Speed = \(\frac{Distance}{Time}\) 1hour = 60 min 5 hour 48 min = ( 5 + \(\frac{48}{60}\) ) hr = \(\frac{29}{5}\) hr Let distance = x km According to question , \(\frac{x}{25}\) + \(\frac{x}{4}\) = \(\frac{29}{5}\) hr \(\frac{29x}{100}\) = \(\frac{29}{5}\) hr x = 20 km |