CUET Preparation Today
If sec θ - tan θ = \(\frac{1}{\sqrt {3 }}\), then value of sec θ is? |
1 \(\frac{2}{\sqrt {3 }}\) 3\(\sqrt {3 }\) \(\frac{1}{\sqrt {3 }}\) |
\(\frac{2}{\sqrt {3 }}\) |
sec θ - tan θ = \(\frac{1}{\sqrt {3 }}\) ............(i) then sec θ + tan θ = \(\sqrt {3}\) adding the equation 2 sec θ = \(\sqrt {3 }\) + \(\frac{1}{\sqrt {3 }}\) ⇒ 2sec θ = \(\frac{4}{\sqrt {3 }}\) or sec θ = \(\frac{2}{\sqrt {3 }}\) |
