If cot A = tan (2A - 45°), A is an acute angle then tan A is equal to:

Given :-

cot A = tan (2A - 45°)

We know ,

tan X = cot Y if X + Y = 90º

So , A + 2A - 45° = 90°

3A = 135°

A = 45°

Now, tanA = tan 45°

= 1