CUET Preparation Today
If cot A = tan (2A - 45°), A is an acute angle then tan A is equal to: |
$\frac{1}{2}$ 0 $\sqrt{3}$ 1 |
1 |
Given :- cot A = tan (2A - 45°) We know , tan X = cot Y if X + Y = 90º So , A + 2A - 45° = 90° 3A = 135° A = 45° Now, tanA = tan 45° = 1 |
