Practicing Success
Practicing Success
CUET Preparation Today
The energy of a hydrogen atom in its ground state is -13.6 eV. The energy of the level corresponding to the quantum number n = 2 (first excited state) in the hydrogen atom is |
-2.72 eV -0.85 eV -0.54 eV -3.4 eV |
-3.4 eV |
$E_n=\frac{-13.6}{n^2}=\frac{-13.6}{4}=-3.4 eV$ |
