A team of 20 men is supposed to do a work in 35 days. After 20 days, 5 more men were employed on work due to this the work is complete 1 day earlier. If 5 more men were not employed how many days would it have been delay.

2\(\frac{1}{2}\)

Work done = 20M × 20D

Now remaining work:

i) 20 men will do remaining work in next 15 days.

ii) 25 men will do remaining work in next 14 days.

Here, we can see, case i) is not possible because if same group of 20 men finish the remaining work then there is no need of extra person.

Therefore, the remaining work = 25 × 14

Hence, Remaining work done by 20 person in =  \(\frac{25\;×\;14}{20}\) = \(\frac{35}{2}\) = 17\(\frac{1}{2}\) days.

Hence, the work will be delay by 17\(\frac{1}{2}\) - 15 = 2\(\frac{1}{2}\) day.