The angle of depression of a point from the top a tree situated at a distance of 10 meter from the base of a tree is 45°. The height of the tree will be

10 meter

tan45º = \(\frac{AB}{BC}\)

Also , tan45º  = 1

On compairing ,

\(\frac{AB}{BC}\) = 1

AB = BC

As, BC = 10 m    (Given )

⇒ AB = 10m

The correct answer is option (1) : 10 meter