The angle of depression of a point from the top a tree situated at a distance of 10 meter from the base of a tree is 45°. The height of the tree will be
Answer & explanation
Correct answer: option 1
tan45º = \(\frac{AB}{BC}\)
Also , tan45º = 1
On compairing ,
\(\frac{AB}{BC}\) = 1
AB = BC
As, BC = 10 m (Given )
⇒ AB = 10m
The correct answer is option (1) : 10 meter