Practicing Success
Match List – I with List – II.
Choose the correct answer from the options given below: |
(1) - (II), (2) – (III), (3) – (I), (D) – (IV) (1) - (III), (2) – (I), (3) – (II), (D) – (IV) (1) - (IV), (2) – (I), (3) – (III), (D) – (II) (1) - (I), (2) – (II), (3) – (III), (D) – (IV) |
(1) - (II), (2) – (III), (3) – (I), (D) – (IV) |
The correct answer is Option (1) → (1) - (II), (2) – (III), (3) – (I), (D) – (IV) For H-atom (Energy) $\underset{(n=1)}{\text {Ground state }} E_I=\frac{-13.6}{1^2} eV=-13.6 eV$ $\underset{(n=2)}{I^{st}\text { excited state }} E_{II}=\frac{-13.6}{2^2} eV=-3.4 eV$ $\underset{(n=4)}{{III}^{rd}\text { excited state }} E_{IV}=\frac{-13.6}{4^2} eV=-8.5 eV$ $\underset{(n=\infty)}{\text { For ionisation }} E_{\infty}=\frac{-13.6}{\infty}=0$ |