Target Exam

CUET

Subject

Chemistry

Chapter

Physical: Electro Chemistry

Question:

Match List-I with List-II

List-I Property

List-II Unit

(A) Cell constant

(I) $cm^{-1}$

(B) Molar conductance

(II) $ohm^{-1}\, cm^2\, mol^{-1}$

(C) Specific conductance

(III) $ohm^{-1}\, cm^{-1}$

(D) Conductance

(IV) $ohm^{-1}$

Choose the correct answer from the options given below:

Options:

(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

(A)-(I), (B)-(III), (C)-(II), (D)-(IV)

(A)-(I), (B)-(II), (C)-(IV), (D)-(III)

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Correct Answer:

(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

Explanation:

The correct answer is Option (1) → (A)-(I), (B)-(II), (C)-(III), (D)-(IV)

List-I Property

List-II Unit

(A) Cell constant

(I) $cm^{-1}$

(B) Molar conductance

(II) $ohm^{-1}\, cm^2\, mol^{-1}$

(C) Specific conductance

(III) $ohm^{-1}\, cm^{-1}$

(D) Conductance

(IV) $ohm^{-1}$

A. Cell Constant ($K$)

$K = \frac{l}{A}$

  • $l \to \text{cm}$
  • $A \to \text{cm}^2$

$K = \frac{\text{cm}}{\text{cm}^2} = \text{cm}^{-1}$

B. Molar Conductance ($\Lambda_m$)

$\Lambda_m = \frac{\kappa}{C}$

  • $\kappa \to \text{S cm}^{-1}$
  • $C \text{ (concentration)} \to \text{mol L}^{-1}$

Convert L to $\text{cm}^3$:

$1\text{L} = 1000\text{cm}^3$

$\Lambda_m = \frac{\text{ohm}^{-1} \text{ cm}^{-1}}{\text{mol cm}^{-3}} = \text{ohm}^{-1} \text{ cm}^2 \text{ mol}^{-1}$

C. Specific Conductance ($\kappa$)

$\kappa = G \frac{l}{A}$

  • $G \to \text{S}$ (Siemens)
  • $l \to \text{cm}$
  • $A \to \text{cm}^2$

$\kappa = \text{ohm}^{-1} \times \frac{\text{cm}}{\text{cm}^2} = \text{ohm}^{-1} \text{ cm}^{-1}$

D. Conductance ($G$)

$G = \frac{1}{R}$

  • Resistance unit = ohm ($\Omega$)

$G = \Omega^{-1} = \text{ohm}^{-1}$