Match List-I with List-II
|
List-I Property |
List-II Unit |
|
(A) Cell constant |
(I) $cm^{-1}$ |
|
(B) Molar conductance |
(II) $ohm^{-1}\, cm^2\, mol^{-1}$ |
|
(C) Specific conductance |
(III) $ohm^{-1}\, cm^{-1}$ |
|
(D) Conductance |
(IV) $ohm^{-1}$ |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → (A)-(I), (B)-(II), (C)-(III), (D)-(IV)
|
List-I Property |
List-II Unit |
|
(A) Cell constant |
(I) $cm^{-1}$ |
|
(B) Molar conductance |
(II) $ohm^{-1}\, cm^2\, mol^{-1}$ |
|
(C) Specific conductance |
(III) $ohm^{-1}\, cm^{-1}$ |
|
(D) Conductance |
(IV) $ohm^{-1}$ |
A. Cell Constant ($K$)
$K = \frac{l}{A}$
- $l \to \text{cm}$
- $A \to \text{cm}^2$
$K = \frac{\text{cm}}{\text{cm}^2} = \text{cm}^{-1}$
B. Molar Conductance ($\Lambda_m$)
$\Lambda_m = \frac{\kappa}{C}$
- $\kappa \to \text{S cm}^{-1}$
- $C \text{ (concentration)} \to \text{mol L}^{-1}$
Convert L to $\text{cm}^3$:
$1\text{L} = 1000\text{cm}^3$
$\Lambda_m = \frac{\text{ohm}^{-1} \text{ cm}^{-1}}{\text{mol cm}^{-3}} = \text{ohm}^{-1} \text{ cm}^2 \text{ mol}^{-1}$
C. Specific Conductance ($\kappa$)
$\kappa = G \frac{l}{A}$
- $G \to \text{S}$ (Siemens)
- $l \to \text{cm}$
- $A \to \text{cm}^2$
$\kappa = \text{ohm}^{-1} \times \frac{\text{cm}}{\text{cm}^2} = \text{ohm}^{-1} \text{ cm}^{-1}$
D. Conductance ($G$)
$G = \frac{1}{R}$
- Resistance unit = ohm ($\Omega$)
$G = \Omega^{-1} = \text{ohm}^{-1}$