$\sin \left[ \frac{\pi}{3} + \sin^{-1} \left( \frac{1}{2} \right) \right]$ is equal to:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $1$ ##
$\sin \left[ \frac{\pi}{3} + \sin^{-1} \left( \frac{1}{2} \right) \right] = \sin \left( \frac{\pi}{3} + \frac{\pi}{6} \right)$
$= \sin \frac{\pi}{2} = 1$