CUET Preparation Today
$\sin \left[ \frac{\pi}{3} + \sin^{-1} \left( \frac{1}{2} \right) \right]$ is equal to: |
$1$ $\frac{1}{2}$ $\frac{1}{3}$ $\frac{1}{4}$ |
$1$ |
The correct answer is Option (1) → $1$ ## $\sin \left[ \frac{\pi}{3} + \sin^{-1} \left( \frac{1}{2} \right) \right] = \sin \left( \frac{\pi}{3} + \frac{\pi}{6} \right)$ $= \sin \frac{\pi}{2} = 1$ |
