If a2 + b2 + c2 \(\frac{1}{a^2}\) + \(\frac{1}{b^2}\) + \(\frac{1}{c^2}\) = 6, a ≠ 0, b ≠ 0, then the value of a5 + b5 + c5 is?
Answer & explanation
Correct answer: option 2
Put a, b, c= 1 (let)
12 + 12 + + 12 + \(\frac{1}{1^2}\) + \(\frac{1}{1^2}\) + + \(\frac{1}{1^2}\) = 6 (satisfied)
Therefore, a5 + b5 + c5 = 15 + 15 + + 15 = 1 + 1 +1 = 3