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If a2 + b2 + c2 \(\frac{1}{a^2}\) + \(\frac{1}{b^2}\) + \(\frac{1}{c^2}\) = 6, a ≠ 0, b ≠ 0, then the value of a5 + b5 + c5 is? |
1 3 4 7 |
3 |
Put a, b, c= 1 (let) 12 + 12 + + 12 + \(\frac{1}{1^2}\) + \(\frac{1}{1^2}\) + + \(\frac{1}{1^2}\) = 6 (satisfied) Therefore, a5 + b5 + c5 = 15 + 15 + + 15 = 1 + 1 +1 = 3 |
