Practicing Success
The angle of depression of a point situated at a distance 100 m from the base of a pole is 30°. Find height of the pole is- |
$100(\sqrt{3}+1)m$ $\frac{100}{3}m$ $\frac{100}{3}\sqrt{3}m$ $100\sqrt{3}m$ |
$\frac{100}{3}\sqrt{3}m$ |
AB is a pole. tan θ = \(\frac{Perp.}{Base}\) tan 30° = \(\frac{AB}{BC}\) \(\frac{1}{\sqrt{3}}\) = \(\frac{AB}{100}\) AB = \(\frac{100}{\sqrt{3}}\) = \(\frac{100}{3}\)\(\sqrt{3}\) m |