In a step-down transformer, 22 kV is converted into 220 V. The number of turns in the primary coil is 60000. The number of turns in the secondary coil will be |
60000 6000 600 60 |
600 |
The correct answer is Option (3) → 600 Given: Primary voltage, $V_p = 22\ \text{kV} = 22000\ \text{V}$ Secondary voltage, $V_s = 220\ \text{V}$ Primary turns, $N_p = 60000$ Using the transformer relation: $\frac{V_p}{V_s} = \frac{N_p}{N_s}$ $\frac{22000}{220} = \frac{60000}{N_s}$ $100 = \frac{60000}{N_s}$ $N_s = \frac{60000}{100} = 600$ Answer: $N_s = 600$ turns |