CUET Preparation Today
Statement I: A sucrose solution in water is dextrorotatory but on hydrolysis in the presence of little HCl, it becomes laevorotatory Statement II: Sucrose on hydrolysis gives unequal amounts of glucose and fructose as a result of which change in sign of rotation is observed |
Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I Both Statement I and Statement II are correct and Statement II is not the correct explanation of Statement I Statement I is correct but Statement II is false Statement I is false but Statement II is correct |
Statement I is correct but Statement II is false |
The correct answer is option 3. Statement I is correct, but Statement II is false. Statement I: A sucrose solution in water is dextrorotatory but on hydrolysis in the presence of little HCl, it becomes laevorotatory Sucrose is dextrorotatory, but on hydrolysis (with dilute HCl), it forms glucose and fructose, and the mixture becomes laevorotatory. This is called inversion of sugar. Statement II: Sucrose on hydrolysis gives unequal amounts of glucose and fructose as a result of which change in sign of rotation is observed Sucrose hydrolyses into equal amounts (1:1) of:
The overall solution becomes laevorotatory not because of unequal amounts, but because fructose has a greater magnitude of rotation than glucose. Therefore, the correct answer is that Statement I is correct, but Statement II is false. |
