If a, b and c are the median, mode and range, respectively of the dat…

Arrange in as Ascending order = 3, 4, 4, 4, 5, 5, 6, 8, 9, 9, 10, 11, 13, 18

 N = 14 which is even

Hence, median (a) = \(\frac{(\frac{n}{2})th\;term\;+\;(\frac{n}{2} +1)th\;term}{2}\) 

                        = \(\frac{7th\;term\;+\;8th\;term}{2}\) 

                       = \(\frac{6+8}{2}\)   = 7

Mode  = is most frequently occurring value in the list. 

i.e.  Mode (b) = 4

Range is the difference between the largest number and smallest number of data.

i.e.  Range (c)= 18-3 = 15

Now, (3a-2b+c) = 3 ×7 - 2×4 + 15 = 21-8+15 = 28