A thief escapes from a police station at 8:00 a.m. on a cycle at a speed of 50 km/h. A policeman starts chasing the thief on a motorbike at 9:30 a.m. at the speed of 65 km/h. At what distance from the police station will the policeman catch up with the thief?
Answer & explanation
Correct answer: option 3
Distance = Speed × Time
Distance cover by thief till 9:30 am = 50 × \(\frac{3 }{2 }\) = 75 km
Relative speed ( when moves in same direction ) = 65 - 50 = 15 km/h
Time taken = \(\frac{Distance }{Speed }\)
= \(\frac{75 }{15 }\) = 5 hours
Distance cover by Policeman = 65 × 5 = 325 km