A dice is thrown twice. Find the probability of getting an odd number in the second throw and a multiple of 3 in the first throw.
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → \(\frac{1}{6}\)
The two throws do not affect each other, so they are independent events, and the probability that both happen is the product of their probabilities. Each throw has 6 equally likely outcomes.
Odd number in the second throw (1, 3, 5): \(\displaystyle\frac{3}{6}=\frac{1}{2}\)
Multiple of 3 in the first throw (3, 6): \(\displaystyle\frac{2}{6}=\frac{1}{3}\)
Both together: \(\displaystyle\frac{1}{2}\times\frac{1}{3}=\frac{1}{6}\)