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Cerium (Z = 58) is an important member of the lanthanoids. Which of the following statements about cerium is incorrect? |
The common oxidation states of cerium are +3 and +4 The +3 oxidation state of cerium is more stable than +4 oxidation state The +4 oxidation state of cerium is not known in solution Cerium (IV) acts as an oxidizing agent |
The +4 oxidation state of cerium is not known in solution |
The correct answer is (3) The +4 oxidation state of cerium is not known in solution Cerium is an important member of the lanthanides, and it can have a variety of oxidation states. The most common oxidation states of cerium are +3 and +4. The +3 oxidation state is more stable than the +4 oxidation state, but the +4 oxidation state is still known in solution. In solution, cerium (IV) is typically found as the cerium(IV) ion, Ce4+. Ce4+ is a strong oxidizing agent, and it can react with other compounds to give them a higher oxidation state. For example, Ce4+ can react with water to give cerium(III) hydroxide, Ce(OH)3, and oxygen gas. Therefore, statement (3) is incorrect. The +4 oxidation state of cerium is known in solution. Here are some additional details about the oxidation states of cerium: The +3 oxidation state of cerium is the most stable oxidation state. It is found in many cerium compounds, such as cerium(III) oxide, Ce2O3, and cerium(III) chloride, CeCl3. The +4 oxidation state of cerium is less stable than the +3 oxidation state. However, it is still known in solution, and it is found in some cerium compounds, such as cerium(IV) oxide, CeO2, and cerium(IV) fluoride, CeF4. Cerium can also have other oxidation states, such as +2, +1, and +0. However, these oxidation states are less common than the +3 and +4 oxidation states. |