Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electrostatic Potential and Capacitance

Question:

A metal of thickness of half the separation between plates of parallel plate capacitor of capacitance is inserted between the plates. What will be the new capacitance?

Options:

C

C/2

Zero

2C

Correct Answer:

2C

Explanation:

C = Co/[1-t/d]

C= original capacitance = C

t = thickness of the conducting slab = d/2

d = separation between the plates =d