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From a conducting sphere of radius R a cavity of radius R/2 is cut out as shown in the figure. At the centre of cavity a point charge q is placed then the electric field and potential at point P as shown in the figure is
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$V=\frac{q}{2 \pi \varepsilon_0 d}, E=\frac{q}{2 \pi \varepsilon_0 d^2}$ $V=\frac{q}{4 \pi \varepsilon_0 d}, E=\frac{q}{2 \pi \varepsilon_0 d^2}$ $V=\frac{q}{4 \pi \varepsilon_0 d}, E=\frac{q}{4 \pi \varepsilon_0 d^2}$ $V=\frac{q}{2 \pi \varepsilon_0 d}, E=\frac{q}{4 \pi \varepsilon_0 d^2}$ |
$V=\frac{q}{4 \pi \varepsilon_0 d}, E=\frac{q}{4 \pi \varepsilon_0 d^2}$ |
$V=\frac{q}{4 \pi \varepsilon_0 d} ; E=\frac{q}{4 \pi \varepsilon_0 d^2}$ |
