The magnetic dipole moment associated with an atom due to orbital motion of an electron in fourth stationary orbit of the hydrogen atom is:

$9.27 \times 10^{-24} A m^2$ $3.708 \times 10^{-23} A m^2$ $2.781 \times 10^{-23} A m^2$ $18.54 \times 10^{-24} A m^2$

$3.708 \times 10^{-23} A m^2$

The correct answer is Option (2) → $3.708 \times 10^{-23} A m^2$