CUET Preparation Today
The magnetic dipole moment associated with an atom due to orbital motion of an electron in fourth stationary orbit of the hydrogen atom is: |
$9.27 \times 10^{-24} A m^2$ $3.708 \times 10^{-23} A m^2$ $2.781 \times 10^{-23} A m^2$ $18.54 \times 10^{-24} A m^2$ |
$3.708 \times 10^{-23} A m^2$ |
The correct answer is Option (2) → $3.708 \times 10^{-23} A m^2$ |
