A 600 pF capacitor is charged by a 150 V battery. The charge on the capacitor is:

90 nC

The correct answer is Option (3) → 90 nC

Given:
Capacitance, $C = 600\,pF = 600 \times 10^{-12}\,F$
Potential difference, $V = 150\,V$

Charge on the capacitor:

$Q = C \times V$

$Q = 600 \times 10^{-12} \times 150 = 9.0 \times 10^{-8}\,C$

∴ Charge on the capacitor = $9.0 \times 10^{-8}\,C$