A 600 pF capacitor is charged by a 150 V battery. The charge on the capacitor is:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → \( 90\,\mathrm{nC} \)
The charge on a capacitor is \( Q = CV \). Convert picofarad to farad first.
\( \displaystyle C = 600\,\mathrm{pF} = 600\times10^{-12}\,\mathrm{F} \)
\( \displaystyle Q = 600\times10^{-12}\times150 = 9\times10^{-8}\,\mathrm{C} = 90\,\mathrm{nC} \)