\(\int \frac{\sin^2x}{1+\cos x}dx\)=
Answer & explanation
Correct answer: option 1
\(\int \frac{\sin^2xdx}{1+\cos x}=\int\frac{1-\cos^2x}{1+\cos^2x}dx\)
$=\int 1-\cos x dx$
$=x-\sin x+C$
\(\int \frac{\sin^2x}{1+\cos x}dx\)=
Correct answer: option 1
\(\int \frac{\sin^2xdx}{1+\cos x}=\int\frac{1-\cos^2x}{1+\cos^2x}dx\)
$=\int 1-\cos x dx$
$=x-\sin x+C$