The internal energy change in a system that has absorbed 5 Kcals of heat and done 1000 J of work is:
Answer & explanation
Correct answer: option 3
Q = \(\Delta\) U + W
\(\Delta\) U = Q - W
= 5 x 4.2 x 1000 - 1000
= 20000 J
The internal energy change in a system that has absorbed 5 Kcals of heat and done 1000 J of work is:
Correct answer: option 3
Q = \(\Delta\) U + W
\(\Delta\) U = Q - W
= 5 x 4.2 x 1000 - 1000
= 20000 J