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CUET
Physics
Thermodynamics
The internal energy change in a system that has absorbed 5 Kcals of heat and done 1000 J of work is:
7900 J
2000 J
20000 J
3950 J
Q = \(\Delta\) U + W
\(\Delta\) U = Q - W
= 5 x 4.2 x 1000 - 1000
= 20000 J