In the given figure, the current through the 20 V battery is: |
11 A 12 A 7 A 14 A |
11 A |
Potential difference across 4Ω resistance (20 + 16)V current through 4Ω resistance = 36V = $\frac{36}{4}$ = 9A [From top to bottom] Similarly, current through 2Ω resistance = $\frac{20-46}{2}$ = 2A |