The first line in the Lyman series has wavelength λ. The wavelength of the first line in Balmer series is :
Answer & explanation
Correct answer: option 4
For first line in Lyman series $\lambda_{L_1}=\frac{4}{3 R}$ ...... (i)
For first line in Balmer series $\lambda_{B_1}=\frac{36}{5 R}$ ...... (ii)
From equation (i) and (ii)
$\frac{\lambda_{B_1}}{\lambda_{L_1}}=\frac{27}{5} \Rightarrow \lambda_{B_1}=\frac{27}{5} \lambda_{L_1} \Rightarrow \lambda_{B_1}=\frac{27}{5} \lambda$