If $f(x)=x^2;x \in (-2, 3),$ then absolute maximum and absolute minimum values (if any) are :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → Absolute maximum does not exist, absolute minimum = 0.
$f(x)=x^2$
for critical points,
$f'(c)=0$
$⇒2x=0$
$⇒x=0$
Now,
$f''(0)=2>0$
∴ $x=0$ is a local minima.