Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Numbers, Quantification and Numerical Applications

Question:

In a one kilometer race, Shreeman beats Ratnam by 250 meters or 2 seconds. Shreeman finish the race in :

Options:

8 seconds

6 seconds

4 seconds

10 seconds

Correct Answer:

6 seconds

Explanation:

The correct answer is Option (2) → 6 seconds

Since Ratnam is 250 m behind when Shreeman,

$V_R=\frac{750}{T}=\frac{1000}{T+2}$

$⇒250T=1500$

$⇒T=6\,seconds$