The function \(f(x) = 2x^3 - 21x^2 + 60x + 3\) is decreasing in the interval
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → \((2, 5)\)
A function is decreasing where \(f'(x) \lt 0\).
\(f'(x) = 6x^2 - 42x + 60\)
\(f'(x) = 6(x^2 - 7x + 10)\)
\(f'(x) = 6(x - 2)(x - 5)\)
The sign of f’(x) changes at x = 2 and x = 5:
\(x \lt 2\): both factors negative, \(f'(x) \gt 0\)
\(2 \lt x \lt 5\): factors of opposite signs, \(f'(x) \lt 0\)
\(x \gt 5\): both factors positive, \(f'(x) \gt 0\)
So f is decreasing in (2, 5) and increasing in \((-\infty, 2)\) and in \((5, \infty)\).